Clay Lab Report

By: Samantha Anderson Block 3 solve: The purpose of this experiment is to contact if and how energizing energy and lift are related. Hypothesis: If energising energy and height are related, then when the height is increased, the kinetic energy increases also because it has to a greater extent potential energy to position with. Material list/ setup diagram: * Clay * Wax paper * matchless thousand stick * Dropper * Water * One fictitious character of material (preferably one of the heaviest) * receive piston chamber * woody block Procedure: 1. get ahead materials. 2. Using the wax paper, tightten permit come forth the clay with the wooden block so you afford abundant room to ignore the thumping on it. 3. accept up the graduated piston chamber with irrigate. 4. Do the first examination beginning at 20 cm and drop the ball onto the clay. 5. imbibe the ball out of the clay. 6. Fill up the eye dropper with the body of water from the graduated cylinder and count how many drops it takes to close up the dent with the water (try to make the water as flat as possible). 7. When the locating is filled and the number of drops is counted, immortalise your data. 8. Do two more than trials starting at 20 cm. 9. retell steps 2-8 until you ingest three trials for 20 cm, 40 cm, 60 cm, 80 cm, and blow cm (1 meter).

Data array: energizing energy vs. vertex efflorescence (cm)| essay one(#of drops)| Trial two(#of drops)| Trial three(#of drops)| Average(#of drops)| amphetamine (m/S)| (.2m) 20cm| 15| 10| 10| 11.7| 1.98| (.4m) 40cm| 15| 18| 16| 16.3| 2.8| (.6) 60cm| 22| 18| 19| 19.7| 3.43| (.8) 80cm| 23| 23| 25| 23.7| 3.96| (1m) 100cm| 28| 24| 26| 26| 4.43| interpret: Calculations: 20cm: 40cm:60cm: Height=20cmheight=40cmheight=60cm Y=(1/2)gt^2y=(1/2)gt^2y=(1/2)gt^2 20=(1/2)(9.8)t^240=(1/2)(9.8)t^260=(1/2)(9.8)t^2 Time= .2 secondstime=.29 secondstime=.35 seconds V=gtv=gtv=gt V=(9.8)(.2)v=(9.8)(.29)v=(9.8)(.35) Velocity= 1.98m/s...If you want to mystify a full essay, mold it on our website: Ordercustompaper.com

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